What are the solutions to the equation 6x^2+4=11x ?

The solutions to the equation 6x^2+4=11x are x= 4/3 ,x= 1/2

Find the zeros of 6x^2+4=11x

The zeros of 6x^2+4=11x are x= 4/3 ,x= 1/2

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6 x^{2} + 4 = 11 x

x = \frac{4}{3}, x = \frac{1}{2}

Decimal Notation

x = 1.33333 \dots, x = 0.5

Solution steps

6 x^{2} + 4 = 11 x

Move

11 x

to the left side

6 x^{2} + 4 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 11 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 \cdot 4 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 6}

x = \frac{- ( - 11 ) + 5}{2 \cdot 6} : \frac{4}{3}

x = \frac{- ( - 11 ) - 5}{2 \cdot 6} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{1}{2}

\frac{- 36 x ^{4} y + 144 x ^{2} y ^{6}}{- 4 x ^{2} y}

x^{2} + 11 x - 12 = 0

∣ x + 6 ∣ = 3

3 x^{2} - 16 x - 3 = - 9 x + 3

\frac{( 2 x ^{4} y ^{0} ) ^{2}}{x ^{6}}

What are the solutions to the equation 6x^2+4=11x ?
The solutions to the equation 6x^2+4=11x are x= 4/3 ,x= 1/2
Find the zeros of 6x^2+4=11x
The zeros of 6x^2+4=11x are x= 4/3 ,x= 1/2