What are the solutions to the equation 42x^2-19x=-2 ?

The solutions to the equation 42x^2-19x=-2 are x= 2/7 ,x= 1/6

Find the zeros of 42x^2-19x=-2

The zeros of 42x^2-19x=-2 are x= 2/7 ,x= 1/6

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42 x^{2} - 19 x = - 2

x = \frac{2}{7}, x = \frac{1}{6}

Decimal Notation

x = 0.28571 \dots, x = 0.16666 \dots

Solution steps

42 x^{2} - 19 x = - 2

Move

2

to the left side

42 x^{2} - 19 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 42 \cdot 2}{2 \cdot 42}

(- 19)^{2} - 4 \cdot 42 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 19 ) \pm 5}{2 \cdot 42}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 5}{2 \cdot 42}, x_{2} = \frac{- ( - 19 ) - 5}{2 \cdot 42}

x = \frac{- ( - 19 ) + 5}{2 \cdot 42} : \frac{2}{7}

x = \frac{- ( - 19 ) - 5}{2 \cdot 42} : \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = \frac{1}{6}

5 x^{2} - 7 x - 2 = 0

- 1.5 + 3 x = 12.5 - 4 x

x^{2} - 6 x + 1 = \frac{3 x + 5}{2}

\frac{6}{\frac{1}{2}}

(4 y + 2)^{2} = 4

What are the solutions to the equation 42x^2-19x=-2 ?
The solutions to the equation 42x^2-19x=-2 are x= 2/7 ,x= 1/6
Find the zeros of 42x^2-19x=-2
The zeros of 42x^2-19x=-2 are x= 2/7 ,x= 1/6