What are the solutions to the equation x^2-8x=242 ?

The solutions to the equation x^2-8x=242 are x=4+sqrt(258),x=4-sqrt(258)

Find the zeros of x^2-8x=242

The zeros of x^2-8x=242 are x=4+sqrt(258),x=4-sqrt(258)

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x^{2} - 8 x = 242

x = 4 + 258, x = 4 - 258

Decimal Notation

x = 20.06237 \dots, x = - 12.06237 \dots

Solution steps

x^{2} - 8 x = 242

Move

242

to the left side

x^{2} - 8 x - 242 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 242 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 242) = 2258

x_{1, 2} = \frac{- ( - 8 ) \pm 2 258}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 258}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 258}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 258}{2 \cdot 1} : 4 + 258

x = \frac{- ( - 8 ) - 2 258}{2 \cdot 1} : 4 - 258

The solutions to the quadratic equation are:

x = 4 + 258, x = 4 - 258

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What are the solutions to the equation x^2-8x=242 ?
The solutions to the equation x^2-8x=242 are x=4+sqrt(258),x=4-sqrt(258)
Find the zeros of x^2-8x=242
The zeros of x^2-8x=242 are x=4+sqrt(258),x=4-sqrt(258)