What is (4-2x)/(3x+4)<= 0 ?

The solution to (4-2x)/(3x+4) = 2

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(4-2x)/(3x+4)<= 0

\frac{4 - 2 x}{3 x + 4} \leq 0

x < - \frac{4}{3} or x \geq 2

Interval Notation

(- \infty, - \frac{4}{3}) \cup [2, \infty)

Decimal Notation

x < - 1.33333 \dots or x \geq 2

Solution steps

\frac{4 - 2 x}{3 x + 4} \leq 0

Factor

\frac{4 - 2 x}{3 x + 4} : \frac{- 2 ( x - 2 )}{3 x + 4}

\frac{- 2 ( x - 2 )}{3 x + 4} \leq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 2 ) ) ( - 1 )}{3 x + 4} \geq 0 \cdot (- 1)

Simplify

\frac{2 ( x - 2 )}{3 x + 4} \geq 0

Divide both sides by

2

\frac{\frac{2 ( x - 2 )}{3 x + 4}}{2} \geq \frac{0}{2}

Simplify

\frac{x - 2}{3 x + 4} \geq 0

Identify the intervals

x < - \frac{4}{3} or x \geq 2

a^{2} = - 49

\frac{130.1724375 - 124}{4.1 - 4}

x^{2} - 8 x - 128 = 0

\frac{25 - 3}{25}

\frac{7 π}{4} \cdot \frac{180}{π}

What is (4-2x)/(3x+4)<= 0 ?
The solution to (4-2x)/(3x+4)<= 0 is x<-4/3 \lor x>= 2