What is the answer to 3(x+4)-3x+13=[(x-2)+4(x+1)]-6x ?

The answer to 3(x+4)-3x+13=[(x-2)+4(x+1)]-6x is x=-23

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3(x+4)-3x+13=[(x-2)+4(x+1)]-6x

3 (x + 4) - 3 x + 13 = [(x - 2) + 4 (x + 1)] - 6 x

x = - 23

Solution steps

3 (x + 4) - 3 x + 13 = [(x - 2) + 4 (x + 1)] - 6 x

Remove parentheses:

(a) = a

3 (x + 4) - 3 x + 13 = x - 2 + 4 (x + 1) - 6 x

Group like terms

3 (x + 4) - 3 x + 13 = x - 6 x + 4 (x + 1) - 2

Add similar elements:

x - 6 x = - 5 x

3 (x + 4) - 3 x + 13 = - 5 x + 4 (x + 1) - 2

Expand

3 (x + 4) - 3 x + 13 : 25

Expand

- 5 x + 4 (x + 1) - 2 : - x + 2

25 = - x + 2

Move

25

to the right side

0 = - x - 23

Move

0

to the right side

= - x - 23

Move

x

to the left side

x = - 23

x^{5} + x^{3} y^{2} + x y^{4} + x^{4} + x^{2} y^{2} + y^{4}

\frac{6 \cdot 3}{6 + 3}

(x + 2)^{2} = 16

(3 - 4 i) (- 3 + 2 i)

2 (x + 1)^{2} - 6 (x + 1) + 4

What is the answer to 3(x+4)-3x+13=[(x-2)+4(x+1)]-6x ?
The answer to 3(x+4)-3x+13=[(x-2)+4(x+1)]-6x is x=-23
Solve for x: 3(x+4)-3x+13=[(x-2)+4(x+1)]-6x
The solution is x=-23