What are the solutions to the equation 9x^2+4x-16=0 ?

The solutions to the equation 9x^2+4x-16=0 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9

Find the zeros of 9x^2+4x-16=0

The zeros of 9x^2+4x-16=0 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9

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9 x^{2} + 4 x - 16 = 0

x = \frac{2 ( 37 - 1 )}{9}, x = - \frac{2 ( 1 + 37 )}{9}

Solution steps

9 x^{2} + 4 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 ( - 16 )}{2 \cdot 9}

4^{2} - 4 \cdot 9 (- 16) = 437

x_{1, 2} = \frac{- 4 \pm 4 37}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 4 + 4 37}{2 \cdot 9}, x_{2} = \frac{- 4 - 4 37}{2 \cdot 9}

x = \frac{- 4 + 4 37}{2 \cdot 9} : \frac{2 ( 37 - 1 )}{9}

x = \frac{- 4 - 4 37}{2 \cdot 9} : - \frac{2 ( 1 + 37 )}{9}

The solutions to the quadratic equation are:

x = \frac{2 ( 37 - 1 )}{9}, x = - \frac{2 ( 1 + 37 )}{9}

\frac{2 x - 7}{4} = \frac{x + 3}{3}

\frac{x - 12}{4} + \frac{x}{2} + \frac{x + 2 x}{9} = 0

2 x^{3} - 5 x^{2} + x + 2

x^{\frac{5}{4}}

x - (2 x + 1) = 8 - (3 x + 3)

What are the solutions to the equation 9x^2+4x-16=0 ?
The solutions to the equation 9x^2+4x-16=0 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9
Find the zeros of 9x^2+4x-16=0
The zeros of 9x^2+4x-16=0 are x=(2(sqrt(37)-1))/9 ,x=-(2(1+sqrt(37)))/9