What is the answer to (2x-7)/4 =(x+3)/3 ?

The answer to (2x-7)/4 =(x+3)/3 is x= 33/2

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(2x-7)/4 =(x+3)/3

\frac{2 x - 7}{4} = \frac{x + 3}{3}

x = \frac{33}{2}

Solution steps

\frac{2 x - 7}{4} = \frac{x + 3}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x - 7) \cdot 3 = 4 (x + 3)

Expand

(2 x - 7) \cdot 3 : 6 x - 21

Expand

4 (x + 3) : 4 x + 12

6 x - 21 = 4 x + 12

Move

21

to the right side

6 x = 4 x + 33

Move

4 x

to the left side

2 x = 33

Divide both sides by

2

x = \frac{33}{2}

\frac{x - 12}{4} + \frac{x}{2} + \frac{x + 2 x}{9} = 0

2 x^{3} - 5 x^{2} + x + 2

x^{\frac{5}{4}}

x - (2 x + 1) = 8 - (3 x + 3)

y^{2} - 5 y + 6 = 0

What is the answer to (2x-7)/4 =(x+3)/3 ?
The answer to (2x-7)/4 =(x+3)/3 is x= 33/2
Solve for x: (2x-7)/4 =(x+3)/3
The solution is x= 33/2