What are the solutions to the equation w^2-5w+2=0 ?

The solutions to the equation w^2-5w+2=0 are w=(5+sqrt(17))/2 ,w=(5-sqrt(17))/2

Find the zeros of w^2-5w+2=0

The zeros of w^2-5w+2=0 are w=(5+sqrt(17))/2 ,w=(5-sqrt(17))/2

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w^{2} - 5 w + 2 = 0

w = \frac{5 + 17}{2}, w = \frac{5 - 17}{2}

Decimal Notation

w = 4.56155 \dots, w = 0.43844 \dots

Solution steps

w^{2} - 5 w + 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 2 = 17

w_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 1}

w = \frac{- ( - 5 ) + 17}{2 \cdot 1} : \frac{5 + 17}{2}

w = \frac{- ( - 5 ) - 17}{2 \cdot 1} : \frac{5 - 17}{2}

The solutions to the quadratic equation are:

w = \frac{5 + 17}{2}, w = \frac{5 - 17}{2}

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What are the solutions to the equation w^2-5w+2=0 ?
The solutions to the equation w^2-5w+2=0 are w=(5+sqrt(17))/2 ,w=(5-sqrt(17))/2
Find the zeros of w^2-5w+2=0
The zeros of w^2-5w+2=0 are w=(5+sqrt(17))/2 ,w=(5-sqrt(17))/2