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9(x-11)>17+7xsimplify (-6j^{-8})/(-2(j^{-3))^5}simplify factor ab+cd-bd-acfactor 4sqrt(x-2)>20z-5=z^2-25
Frequently Asked Questions (FAQ)
What are the solutions to the equation 2x^1+5x^2=16 ?
The solutions to the equation 2x^1+5x^2=16 are x= 8/5 ,x=-2Find the zeros of 2x^1+5x^2=16
The zeros of 2x^1+5x^2=16 are x= 8/5 ,x=-2