What is 4sqrt(x-2)>20 ?

The solution to 4sqrt(x-2)>20 is x>27

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4sqrt(x-2)>20

4 x - 2 > 20

x > 27

Interval Notation

(27, \infty)

Solution steps

4 x - 2 > 20

Divide both sides by

4

\frac{4 x - 2}{4} > \frac{20}{4}

Simplify

x - 2 > 5

Square both sides

(x - 2)^{2} > 5^{2}

Simplify

x - 2 > 25

Move

2

to the right side

x > 27

Find singularity points

Find non-negative values for radicals:

x \geq 2

Combine the intervals

x > 27 and x \geq 2

Merge Overlapping Intervals

x > 27

z - 5 = z^{2} - 25

\frac{3 x - 1}{5 x ^{2} - 1} > - 3

2 y^{2} + 9 y - 5

\frac{8.1 \cdot 1 0 ^{4}}{1.8 \cdot 1 0 ^{- 4}}

225 x^{2} - 289 y^{2}