What are the solutions to the equation 4x^2-4x+1=0 ?

The solutions to the equation 4x^2-4x+1=0 are x= 1/2

Find the zeros of 4x^2-4x+1=0

The zeros of 4x^2-4x+1=0 are x= 1/2

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4 x^{2} - 4 x + 1 = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

25 f^{2} + 10 f + 1

(x + 3)^{2} = - 1

- 27

\frac{1}{2} \cdot 4

(2 x^{2})^{4}

What are the solutions to the equation 4x^2-4x+1=0 ?
The solutions to the equation 4x^2-4x+1=0 are x= 1/2
Find the zeros of 4x^2-4x+1=0
The zeros of 4x^2-4x+1=0 are x= 1/2