What are the solutions to the equation -x^2-4x-2=0 ?

The solutions to the equation -x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)

Find the zeros of -x^2-4x-2=0

The zeros of -x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)

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- x^{2} - 4 x - 2 = 0

x = - 2 - 2, x = - 2 + 2

Decimal Notation

x = - 3.41421 \dots, x = - 0.58578 \dots

Solution steps

- x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 2) = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 2}{2 ( - 1 )} : - 2 - 2

x = \frac{- ( - 4 ) - 2 2}{2 ( - 1 )} : - 2 + 2

The solutions to the quadratic equation are:

x = - 2 - 2, x = - 2 + 2

g + 466 \leq - 191

\frac{x ( x - 3 )}{6} - \frac{x}{2} = 0

\frac{6 !}{4 ! \cdot ( 6 - 4 ) !}

2 x + 4 = 20

\frac{x - 6}{x + 2} > 0

What are the solutions to the equation -x^2-4x-2=0 ?
The solutions to the equation -x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)
Find the zeros of -x^2-4x-2=0
The zeros of -x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)