What are the solutions to the equation 0=4x^2-12x+9 ?

The solutions to the equation 0=4x^2-12x+9 are x= 3/2

Find the zeros of 0=4x^2-12x+9

The zeros of 0=4x^2-12x+9 are x= 3/2

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0 = 4 x^{2} - 12 x + 9

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

0 = 4 x^{2} - 12 x + 9

Switch sides

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

(5 x - 1)^{2} = 7

7 x^{2} - 4 x y + 8 y^{2} - 11 x^{2} + 7 x y - 10 y^{2}

x^{2} + 12 x + 36 = 25

\frac{9 + 4 i}{- 8 - 8 i}

\frac{5}{2} \cdot 2

What are the solutions to the equation 0=4x^2-12x+9 ?
The solutions to the equation 0=4x^2-12x+9 are x= 3/2
Find the zeros of 0=4x^2-12x+9
The zeros of 0=4x^2-12x+9 are x= 3/2