en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

64x^2+16x+1>0

Solution

64 x^{2} + 16 x + 1 > 0

Solution

x < - \frac{1}{8} or x > - \frac{1}{8}

+2

Interval Notation

(- \infty, - \frac{1}{8}) \cup (- \frac{1}{8}, \infty)

Decimal Notation

x < - 0.125 or x > - 0.125

Solution steps

64 x^{2} + 16 x + 1 > 0

Factor

64 x^{2} + 16 x + 1 : (8 x + 1)^{2}

(8 x + 1)^{2} > 0

For

u^{n} > 0

, if

n

is even then

u < 0

or

u > 0

8 x + 1 < 0 or 8 x + 1 > 0

8 x + 1 < 0 : x < - \frac{1}{8}

8 x + 1 > 0 : x > - \frac{1}{8}

Combine the intervals

x < - \frac{1}{8} or x > - \frac{1}{8}

Popular Examples

3 x^{2} - 110 = 0

(6x-7)/4+(3x-5)/7 =(5x+78)/(28)

\frac{6 x - 7}{4} + \frac{3 x - 5}{7} = \frac{5 x + 78}{28}

-(x-1)/3+1/5 <= (2x+1)/2-3

- \frac{x - 1}{3} + \frac{1}{5} \leq \frac{2 x + 1}{2} - 3

factor x^2y^2-144 factor

x^{2} y^{2} - 144

simplify 64^{-1/6}simplify

6 4^{- \frac{1}{6}}

Frequently Asked Questions (FAQ)

What is 64x^2+16x+1>0 ?
The solution to 64x^2+16x+1>0 is x<-1/8 \lor x>-1/8