What are the solutions to the equation (x+11/6)^2= 3/4 ?

The solutions to the equation (x+11/6)^2= 3/4 are x=(sqrt(3))/2-11/6 ,x=-(sqrt(3))/2-11/6

Find the zeros of (x+11/6)^2= 3/4

The zeros of (x+11/6)^2= 3/4 are x=(sqrt(3))/2-11/6 ,x=-(sqrt(3))/2-11/6

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(x + \frac{11}{6})^{2} = \frac{3}{4}

x = \frac{3}{2} - \frac{11}{6}, x = - \frac{3}{2} - \frac{11}{6}

Solution steps

(x + \frac{11}{6})^{2} = \frac{3}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + \frac{11}{6} = \frac{3}{4} : x = \frac{3}{2} - \frac{11}{6}

Solve

x + \frac{11}{6} = - \frac{3}{4} : x = - \frac{3}{2} - \frac{11}{6}

The solutions to the quadratic equation are:

x = \frac{3}{2} - \frac{11}{6}, x = - \frac{3}{2} - \frac{11}{6}

x^{2} - 18 x + 80 = 0

\frac{\frac{q}{r} + 1}{\frac{r}{q} - 1}

\frac{( - 3 x ^{- 4} y ) ^{- 4}}{( 5 x ^{- 2} y ^{3} ) ^{0}}

5 x^{2} - 10 x - 5

ln (5 x) + ln (3 x) > 9

What are the solutions to the equation (x+11/6)^2= 3/4 ?
The solutions to the equation (x+11/6)^2= 3/4 are x=(sqrt(3))/2-11/6 ,x=-(sqrt(3))/2-11/6
Find the zeros of (x+11/6)^2= 3/4
The zeros of (x+11/6)^2= 3/4 are x=(sqrt(3))/2-11/6 ,x=-(sqrt(3))/2-11/6