What are the solutions to the equation x=64-x^2 ?

The solutions to the equation x=64-x^2 are x=-(1+sqrt(257))/2 ,x=(sqrt(257)-1)/2

Find the zeros of x=64-x^2

The zeros of x=64-x^2 are x=-(1+sqrt(257))/2 ,x=(sqrt(257)-1)/2

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x = 64 - x^{2}

x = - \frac{1 + 257}{2}, x = \frac{257 - 1}{2}

Solution steps

x = 64 - x^{2}

Switch sides

64 - x^{2} = x

Move

x

to the left side

64 - x^{2} - x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 64}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 64 = 257

x_{1, 2} = \frac{- ( - 1 ) \pm 257}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 257}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 257}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 257}{2 ( - 1 )} : - \frac{1 + 257}{2}

x = \frac{- ( - 1 ) - 257}{2 ( - 1 )} : \frac{257 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 257}{2}, x = \frac{257 - 1}{2}

- 16 t^{2} + 44 t + 28 = 0

5 x - 6 = 2 x + 12

10 \geq j + 5

y - 7.55 = - 4.26

2 y - 1.7 = 3.3

What are the solutions to the equation x=64-x^2 ?
The solutions to the equation x=64-x^2 are x=-(1+sqrt(257))/2 ,x=(sqrt(257)-1)/2
Find the zeros of x=64-x^2
The zeros of x=64-x^2 are x=-(1+sqrt(257))/2 ,x=(sqrt(257)-1)/2