What are the solutions to the equation -x^2+6x-10=0 ?

The solutions to the equation -x^2+6x-10=0 are x=3-i,x=3+i

Find the zeros of -x^2+6x-10=0

The zeros of -x^2+6x-10=0 are x=3-i,x=3+i

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- x^{2} + 6 x - 10 = 0

x = 3 - i, x = 3 + i

Solution steps

- x^{2} + 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 10) : 2 i

x_{1, 2} = \frac{- 6 \pm 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 i}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 i}{2 ( - 1 )}

x = \frac{- 6 + 2 i}{2 ( - 1 )} : 3 - i

x = \frac{- 6 - 2 i}{2 ( - 1 )} : 3 + i

The solutions to the quadratic equation are:

x = 3 - i, x = 3 + i

(\frac{4 p ^{7}}{7 r ^{2}})^{2}

4 a + 8 > 11 a + 15 and 13 - 14 a \leq 13 - 3 a

f^{2} + 28 f - 47 = 0

0 = t^{2} - 190 t - 6000

2 ∣ 6 - 2 x ∣ + 6 = 10

What are the solutions to the equation -x^2+6x-10=0 ?
The solutions to the equation -x^2+6x-10=0 are x=3-i,x=3+i
Find the zeros of -x^2+6x-10=0
The zeros of -x^2+6x-10=0 are x=3-i,x=3+i