What are the solutions to the equation (x+1)^2=7 ?

The solutions to the equation (x+1)^2=7 are x=sqrt(7)-1,x=-sqrt(7)-1

Find the zeros of (x+1)^2=7

The zeros of (x+1)^2=7 are x=sqrt(7)-1,x=-sqrt(7)-1

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(x + 1)^{2} = 7

x = 7 - 1, x = - 7 - 1

Decimal Notation

x = 1.64575 \dots, x = - 3.64575 \dots

Solution steps

(x + 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 7 : x = 7 - 1

Solve

x + 1 = - 7 : x = - 7 - 1

The solutions to the quadratic equation are:

x = 7 - 1, x = - 7 - 1

3 x^{2} + 17 x + 20 = 0

∣ x ∣ \leq 20

3 x + 2 > 11

∣ 6 ∣ < 3

a^{2} - 3 a + 2 ab - 6 b

What are the solutions to the equation (x+1)^2=7 ?
The solutions to the equation (x+1)^2=7 are x=sqrt(7)-1,x=-sqrt(7)-1
Find the zeros of (x+1)^2=7
The zeros of (x+1)^2=7 are x=sqrt(7)-1,x=-sqrt(7)-1