What are the solutions to the equation 3x^2+17x+20=0 ?

The solutions to the equation 3x^2+17x+20=0 are x=-5/3 ,x=-4

Find the zeros of 3x^2+17x+20=0

The zeros of 3x^2+17x+20=0 are x=-5/3 ,x=-4

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3 x^{2} + 17 x + 20 = 0

x = - \frac{5}{3}, x = - 4

Solution steps

3 x^{2} + 17 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 20}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 20 = 7

x_{1, 2} = \frac{- 17 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 7}{2 \cdot 3}, x_{2} = \frac{- 17 - 7}{2 \cdot 3}

x = \frac{- 17 + 7}{2 \cdot 3} : - \frac{5}{3}

x = \frac{- 17 - 7}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - 4

∣ x ∣ \leq 20

3 x + 2 > 11

∣ 6 ∣ < 3

a^{2} - 3 a + 2 ab - 6 b

x^{2} + 10 x - 96 = 0

What are the solutions to the equation 3x^2+17x+20=0 ?
The solutions to the equation 3x^2+17x+20=0 are x=-5/3 ,x=-4
Find the zeros of 3x^2+17x+20=0
The zeros of 3x^2+17x+20=0 are x=-5/3 ,x=-4