What are the solutions to the equation 1/4 (x+5)^2-1=3 ?

The solutions to the equation 1/4 (x+5)^2-1=3 are x=-1,x=-9

Find the zeros of 1/4 (x+5)^2-1=3

The zeros of 1/4 (x+5)^2-1=3 are x=-1,x=-9

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\frac{1}{4} (x + 5)^{2} - 1 = 3

x = - 1, x = - 9

Solution steps

\frac{1}{4} (x + 5)^{2} - 1 = 3

Move

1

to the right side

\frac{1}{4} (x + 5)^{2} = 4

Multiply both sides by

4

(x + 5)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 16 : x = - 1

Solve

x + 5 = - 16 : x = - 9

The solutions to the quadratic equation are:

x = - 1, x = - 9

x^{2} - 3 x = 0

\frac{8}{4 + 4 i}

3 v - 14 < 43

2 x - 3 = x - 15

9 < 4 x + 1 < x + 16

What are the solutions to the equation 1/4 (x+5)^2-1=3 ?
The solutions to the equation 1/4 (x+5)^2-1=3 are x=-1,x=-9
Find the zeros of 1/4 (x+5)^2-1=3
The zeros of 1/4 (x+5)^2-1=3 are x=-1,x=-9