What are the solutions to the equation 3x^2-1x=1x+8 ?

The solutions to the equation 3x^2-1x=1x+8 are x=2,x=-4/3

Find the zeros of 3x^2-1x=1x+8

The zeros of 3x^2-1x=1x+8 are x=2,x=-4/3

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3 x^{2} - 1 x = 1 x + 8

x = 2, x = - \frac{4}{3}

Solution steps

3 x^{2} - 1 \cdot x = 1 \cdot x + 8

Refine

3 x^{2} - x = x + 8

Move

8

to the left side

3 x^{2} - x - 8 = x

Move

x

to the left side

3 x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 3}

x = \frac{- ( - 2 ) + 10}{2 \cdot 3} : 2

x = \frac{- ( - 2 ) - 10}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{4}{3}

6 x = 3

8 x y - 28 x + 18 y - 63

3 (x^{2} - 1) - 2 = - 2

(\frac{3}{2})^{\frac{3}{2}}

x^{2} - 8 x - 2 = 0

What are the solutions to the equation 3x^2-1x=1x+8 ?
The solutions to the equation 3x^2-1x=1x+8 are x=2,x=-4/3
Find the zeros of 3x^2-1x=1x+8
The zeros of 3x^2-1x=1x+8 are x=2,x=-4/3