What is |x-1|>|x+1| ?

The solution to |x-1|>|x+1| is x<0

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|x-1|>|x+1|

∣ x - 1 ∣ > ∣ x + 1 ∣

x < 0

Interval Notation

(- \infty, 0)

Solution steps

∣ x - 1 ∣ > ∣ x + 1 ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < 1, x \geq 1

Solve the inequality for each interval

x < - 1 or - 1 \leq x < 0 or No Solution

Merge Overlapping Intervals

x < 0

lo g_{2} (\frac{1}{2}) = x

2 x^{2} - 13 x + 4 = 0

x^{2} - 22 x - 23

x^{4} + 50 x^{2} + 625

e^{(0)}