What is factor 3w+4w^4+6w^2+2w^3 ?

The solution to factor 3w+4w^4+6w^2+2w^3 is w(2w+1)(2w^2+3)

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factor 3w+4w^4+6w^2+2w^3

factor

3 w + 4 w^{4} + 6 w^{2} + 2 w^{3}

w (2 w + 1) (2 w^{2} + 3)

Solution steps

3 w + 4 w^{4} + 6 w^{2} + 2 w^{3}

Write in the standard form

= 4 w^{4} + 2 w^{3} + 6 w^{2} + 3 w

Factor out common term

w : w (4 w^{3} + 2 w^{2} + 6 w + 3)

= w (4 w^{3} + 2 w^{2} + 6 w + 3)

Factor

4 w^{3} + 2 w^{2} + 6 w + 3 : (2 w + 1) (2 w^{2} + 3)

= w (2 w + 1) (2 w^{2} + 3)

- \frac{3}{2} - (- \frac{3}{4})

2 x^{2} + 7 x - 3 = 0

lo g_{6} (12) + lo g_{6} (3)

96 - 163

\frac{1}{5} y + 11 = 3 - \frac{3}{5} y

What is factor 3w+4w^4+6w^2+2w^3 ?
The solution to factor 3w+4w^4+6w^2+2w^3 is w(2w+1)(2w^2+3)