What are the solutions to the equation e(v)=4v^2 ?

The solutions to the equation e(v)=4v^2 are v=0,v= e/4

Find the zeros of e(v)=4v^2

The zeros of e(v)=4v^2 are v=0,v= e/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e (v) = 4 v^{2}

v = 0, v = \frac{e}{4}

Solution steps

e (v) = 4 v^{2}

Move

4 v^{2}

to the left side

e v - 4 v^{2} = 0

Factor

e v - 4 v^{2} : - v (4 v - e)

- v (4 v - e) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v = 0 or 4 v - e = 0

Solve

4 v - e = 0 : v = \frac{e}{4}

The solutions to the quadratic equation are:

v = 0, v = \frac{e}{4}

2 x + 9 + 3 x + x = 6 x + 1

2 1^{2} + 2 0^{2} = c^{2}

(- 4 b^{3}) (2 b^{5})

x^{2} - 4 x + 2 = 7

\frac{1}{2} x - \frac{3}{5} < 2 - \frac{7}{10} x

What are the solutions to the equation e(v)=4v^2 ?
The solutions to the equation e(v)=4v^2 are v=0,v= e/4
Find the zeros of e(v)=4v^2
The zeros of e(v)=4v^2 are v=0,v= e/4