What is the answer to 2(3x+1)+3x-2+x=2(4x-5)+2(2x-3) ?

The answer to 2(3x+1)+3x-2+x=2(4x-5)+2(2x-3) is x=8

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2(3x+1)+3x-2+x=2(4x-5)+2(2x-3)

2 (3 x + 1) + 3 x - 2 + x = 2 (4 x - 5) + 2 (2 x - 3)

x = 8

Solution steps

2 (3 x + 1) + 3 x - 2 + x = 2 (4 x - 5) + 2 (2 x - 3)

Group like terms

3 x + x + 2 (3 x + 1) - 2 = 2 (4 x - 5) + 2 (2 x - 3)

Add similar elements:

3 x + x = 4 x

4 x + 2 (3 x + 1) - 2 = 2 (4 x - 5) + 2 (2 x - 3)

Expand

4 x + 2 (3 x + 1) - 2 : 10 x

Expand

2 (4 x - 5) + 2 (2 x - 3) : 12 x - 16

10 x = 12 x - 16

Move

12 x

to the left side

- 2 x = - 16

Divide both sides by

- 2

x = 8

lo g_{8} (4096)

3 x^{2} + 4 = 13 x

- x (x - 5) (x + 4) > 0

b^{2} - b - 12

v^{2} - 8 v + 15 = 0

What is the answer to 2(3x+1)+3x-2+x=2(4x-5)+2(2x-3) ?
The answer to 2(3x+1)+3x-2+x=2(4x-5)+2(2x-3) is x=8
Solve for x: 2(3x+1)+3x-2+x=2(4x-5)+2(2x-3)
The solution is x=8