What are the solutions to the equation z^2-10z=-17 ?

The solutions to the equation z^2-10z=-17 are z=5+2sqrt(2),z=5-2sqrt(2)

Find the zeros of z^2-10z=-17

The zeros of z^2-10z=-17 are z=5+2sqrt(2),z=5-2sqrt(2)

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z^{2} - 10 z = - 17

z = 5 + 22, z = 5 - 22

Decimal Notation

z = 7.82842 \dots, z = 2.17157 \dots

Solution steps

z^{2} - 10 z = - 17

Move

17

to the left side

z^{2} - 10 z + 17 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 17 = 42

z_{1, 2} = \frac{- ( - 10 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 4 2}{2 \cdot 1}, z_{2} = \frac{- ( - 10 ) - 4 2}{2 \cdot 1}

z = \frac{- ( - 10 ) + 4 2}{2 \cdot 1} : 5 + 22

z = \frac{- ( - 10 ) - 4 2}{2 \cdot 1} : 5 - 22

The solutions to the quadratic equation are:

z = 5 + 22, z = 5 - 22

6 \cdot 8

48 x - 16 x^{2} = 0

\frac{5}{5} - \frac{2}{5} x = 540 - \frac{3}{5} x - 86

5 + x < 1

x^{2} - 2 x - 1 \leq 0

What are the solutions to the equation z^2-10z=-17 ?
The solutions to the equation z^2-10z=-17 are z=5+2sqrt(2),z=5-2sqrt(2)
Find the zeros of z^2-10z=-17
The zeros of z^2-10z=-17 are z=5+2sqrt(2),z=5-2sqrt(2)