What are the solutions to the equation (x+3)^2-8x-9=0 ?

The solutions to the equation (x+3)^2-8x-9=0 are x=2,x=0

Find the zeros of (x+3)^2-8x-9=0

The zeros of (x+3)^2-8x-9=0 are x=2,x=0

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(x + 3)^{2} - 8 x - 9 = 0

x = 2, x = 0

Solution steps

(x + 3)^{2} - 8 x - 9 = 0

Expand

(x + 3)^{2} - 8 x - 9 : x^{2} - 2 x

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

7 m - 8 > 6

\frac{x + 2}{3} - \frac{2 x - 1}{2} = 4

\frac{1}{2} x - \frac{4}{3} > 3

\frac{3}{5} + \frac{3}{10}

19 x = - 34 - x^{2}

What are the solutions to the equation (x+3)^2-8x-9=0 ?
The solutions to the equation (x+3)^2-8x-9=0 are x=2,x=0
Find the zeros of (x+3)^2-8x-9=0
The zeros of (x+3)^2-8x-9=0 are x=2,x=0