What are the solutions to the equation x^2=6x+40 ?

The solutions to the equation x^2=6x+40 are x=10,x=-4

Find the zeros of x^2=6x+40

The zeros of x^2=6x+40 are x=10,x=-4

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x^{2} = 6 x + 40

x = 10, x = - 4

Solution steps

x^{2} = 6 x + 40

Move

40

to the left side

x^{2} - 40 = 6 x

Move

6 x

to the left side

x^{2} - 40 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

x_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

x = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

x = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 10, x = - 4

5 x^{4} - 135 x

105 xuv + 60 xv - 70 xu - 90 x v^{2}

- 7 (x - 2) - 20 = - 6

0 = x^{2} + 8 x + 13

\frac{16}{3} \cdot 2

What are the solutions to the equation x^2=6x+40 ?
The solutions to the equation x^2=6x+40 are x=10,x=-4
Find the zeros of x^2=6x+40
The zeros of x^2=6x+40 are x=10,x=-4