What is 6x-3(x-1)<3(x+2) ?

The solution to 6x-3(x-1)<3(x+2) is True for all x

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6x-3(x-1)<3(x+2)

6 x - 3 (x - 1) < 3 (x + 2)

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

6 x - 3 (x - 1) < 3 (x + 2)

Expand

- 3 (x - 1) : - 3 x + 3

6 x - 3 x + 3 < 3 (x + 2)

Add similar elements:

6 x - 3 x = 3 x

3 x + 3 < 3 (x + 2)

Expand

3 (x + 2) : 3 x + 6

3 x + 3 < 3 x + 6

Move

3

to the right side

3 x < 3 x + 3

Move

3 x

to the left side

0 < 3

Therefore, the solution is

True for all x

∣ 6 + 3 x ∣ + 10 = 21

p^{2} - \frac{6}{5} p + \frac{9}{25} = 0

2 - 3 a \leq 1

(y + 3)^{2} = - 4 (3 - 2)

7^{- 2} \cdot 7^{- 6}