What are the solutions to the equation 5x^2+45x+90=0 ?

The solutions to the equation 5x^2+45x+90=0 are x=-3,x=-6

Find the zeros of 5x^2+45x+90=0

The zeros of 5x^2+45x+90=0 are x=-3,x=-6

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5 x^{2} + 45 x + 90 = 0

x = - 3, x = - 6

Solution steps

5 x^{2} + 45 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 5 \cdot 90}{2 \cdot 5}

4 5^{2} - 4 \cdot 5 \cdot 90 = 15

x_{1, 2} = \frac{- 45 \pm 15}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 45 + 15}{2 \cdot 5}, x_{2} = \frac{- 45 - 15}{2 \cdot 5}

x = \frac{- 45 + 15}{2 \cdot 5} : - 3

x = \frac{- 45 - 15}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - 3, x = - 6

\frac{π}{3} \cdot \frac{180}{π}

x^{2} + (x + 3)^{2} - 89 = 0

w^{2} - w - 6 = 0

(a^{- 2} + b^{- 2})^{- 1}

2 x^{2} = 10 x

What are the solutions to the equation 5x^2+45x+90=0 ?
The solutions to the equation 5x^2+45x+90=0 are x=-3,x=-6
Find the zeros of 5x^2+45x+90=0
The zeros of 5x^2+45x+90=0 are x=-3,x=-6