What is (3n^2-5n-2)/(2n-4) ?

The solution to (3n^2-5n-2)/(2n-4) is (3n+1)/2

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simplify (3n^2-5n-2)/(2n-4)

simplify

\frac{3 n ^{2} - 5 n - 2}{2 n - 4}

\frac{3 n + 1}{2}

Solution steps

\frac{3 n ^{2} - 5 n - 2}{2 n - 4}

Factor

3 n^{2} - 5 n - 2 : (3 n + 1) (n - 2)

= \frac{( 3 n + 1 ) ( n - 2 )}{2 n - 4}

Factor

2 n - 4 : 2 (n - 2)

= \frac{( 3 n + 1 ) ( n - 2 )}{2 ( n - 2 )}

Cancel the common factor:

n - 2

= \frac{3 n + 1}{2}

x^{2} - 10 x + 23 = 0

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x^{3} + x^{2} + 3 x - 5