What is the answer to (t+3)/7+(t-1)/3 =4 ?

The answer to (t+3)/7+(t-1)/3 =4 is t= 41/5

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(t+3)/7+(t-1)/3 =4

\frac{t + 3}{7} + \frac{t - 1}{3} = 4

t = \frac{41}{5}

Decimal Notation

t = 8.2

Solution steps

\frac{t + 3}{7} + \frac{t - 1}{3} = 4

Multiply by LCM

3 (t + 3) + 7 (t - 1) = 84

Expand

3 (t + 3) + 7 (t - 1) : 10 t + 2

10 t + 2 = 84

Move

2

to the right side

10 t = 82

Divide both sides by

10

t = \frac{41}{5}

\frac{- 50}{- 50 - 3}

2 (x + 9)^{2} = 90

64 x^{2} - 165 x + 5 = 0

2 ∣ x - 4 ∣ - 7 \leq 1

3 x^{3} - 27 x

What is the answer to (t+3)/7+(t-1)/3 =4 ?
The answer to (t+3)/7+(t-1)/3 =4 is t= 41/5
Solve for t: (t+3)/7+(t-1)/3 =4
The solution is t= 41/5