What are the solutions to the equation -2x^22-6=0 ?

The solutions to the equation -2x^22-6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of -2x^22-6=0

The zeros of -2x^22-6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

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- 2 x^{2} 2 - 6 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

- 2 x^{2} \cdot 2 - 6 = 0

Move

6

to the right side

- 2 x^{2} \cdot 2 = 6

Divide both sides by

- 2 \cdot 2

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

5 t^{- 2} \cdot 2 t^{- 5}

x^{2} - 5 x - 24 > 0

\frac{x}{6} + 4 = 25

\frac{r ^{5}}{g ^{- 3}}

x^{2} + 2 x - 36 = 2 x

What are the solutions to the equation -2x^22-6=0 ?
The solutions to the equation -2x^22-6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of -2x^22-6=0
The zeros of -2x^22-6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i