What is 5t^{-2}*2t^{-5} ?

The solution to 5t^{-2}*2t^{-5} is (10)/(t^7)

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simplify 5t^{-2}*2t^{-5}

simplify

5 t^{- 2} \cdot 2 t^{- 5}

\frac{10}{t ^{7}}

Solution steps

5 t^{- 2} \cdot 2 t^{- 5}

Multiply the numbers:

5 \cdot 2 = 10

= 10 t^{- 2} t^{- 5}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t^{- 2} t^{- 5} = t^{- 2 - 5}

= 10 t^{- 2 - 5}

Subtract the numbers:

- 2 - 5 = - 7

= 10 t^{- 7}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

t^{- 7} = \frac{1}{t ^{7}}

= 10 \cdot \frac{1}{t ^{7}}

Simplify

10 \cdot \frac{1}{t ^{7}} : \frac{10}{t ^{7}}

= \frac{10}{t ^{7}}

x^{2} - 5 x - 24 > 0

\frac{x}{6} + 4 = 25

\frac{r ^{5}}{g ^{- 3}}

x^{2} + 2 x - 36 = 2 x

- 36 s^{2} - 3 = 0