What are the solutions to the equation -36s^2-3=0 ?

The solutions to the equation -36s^2-3=0 are s= 1/(2sqrt(3))i,s=-1/(2sqrt(3))i

Find the zeros of -36s^2-3=0

The zeros of -36s^2-3=0 are s= 1/(2sqrt(3))i,s=-1/(2sqrt(3))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 36 s^{2} - 3 = 0

s = \frac{1}{2 3} i, s = - \frac{1}{2 3} i

Solution steps

- 36 s^{2} - 3 = 0

Move

3

to the right side

- 36 s^{2} = 3

Divide both sides by

- 36

s^{2} = - \frac{1}{12}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - \frac{1}{12}, s = - - \frac{1}{12}

- \frac{1}{12} = \frac{1}{2 3} i

- - \frac{1}{12} = - \frac{1}{2 3} i

s = \frac{1}{2 3} i, s = - \frac{1}{2 3} i

4 x^{2} - 56 x + 180 = 0

- 15 \leq 3 x + 6 < - 9

\frac{x}{3} + \frac{x}{2} = 15

3 x - 9 x^{2} + 10 = 0

x + 8 \leq 13

What are the solutions to the equation -36s^2-3=0 ?
The solutions to the equation -36s^2-3=0 are s= 1/(2sqrt(3))i,s=-1/(2sqrt(3))i
Find the zeros of -36s^2-3=0
The zeros of -36s^2-3=0 are s= 1/(2sqrt(3))i,s=-1/(2sqrt(3))i