What are the solutions to the equation -3x^2+3x+2=0 ?

The solutions to the equation -3x^2+3x+2=0 are x=-(-3+sqrt(33))/6 ,x=(3+sqrt(33))/6

Find the zeros of -3x^2+3x+2=0

The zeros of -3x^2+3x+2=0 are x=-(-3+sqrt(33))/6 ,x=(3+sqrt(33))/6

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- 3 x^{2} + 3 x + 2 = 0

x = - \frac{- 3 + 33}{6}, x = \frac{3 + 33}{6}

Decimal Notation

x = - 0.45742 \dots, x = 1.45742 \dots

Solution steps

- 3 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 2 = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 ( - 3 )}, x_{2} = \frac{- 3 - 33}{2 ( - 3 )}

x = \frac{- 3 + 33}{2 ( - 3 )} : - \frac{- 3 + 33}{6}

x = \frac{- 3 - 33}{2 ( - 3 )} : \frac{3 + 33}{6}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 33}{6}, x = \frac{3 + 33}{6}

(x - 8)^{2} + x^{2} = (x + 8)^{2}

\frac{a + 6}{3} = \frac{2 a + 4}{5}

\frac{2}{5} x - 6 = 8

\frac{x}{3} + \frac{2}{3} = \frac{5}{3}

x^{2} + 10 x + 61 = 0

What are the solutions to the equation -3x^2+3x+2=0 ?
The solutions to the equation -3x^2+3x+2=0 are x=-(-3+sqrt(33))/6 ,x=(3+sqrt(33))/6
Find the zeros of -3x^2+3x+2=0
The zeros of -3x^2+3x+2=0 are x=-(-3+sqrt(33))/6 ,x=(3+sqrt(33))/6