What are the solutions to the equation -16t^2+100+75=0 ?

The solutions to the equation -16t^2+100+75=0 are t=(5sqrt(7))/4 ,t=-(5sqrt(7))/4

Find the zeros of -16t^2+100+75=0

The zeros of -16t^2+100+75=0 are t=(5sqrt(7))/4 ,t=-(5sqrt(7))/4

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- 16 t^{2} + 100 + 75 = 0

t = \frac{5 7}{4}, t = - \frac{5 7}{4}

Decimal Notation

t = 3.30718 \dots, t = - 3.30718 \dots

Solution steps

- 16 t^{2} + 100 + 75 = 0

Move

100

to the right side

- 16 t^{2} + 75 = - 100

Move

75

to the right side

- 16 t^{2} = - 175

Divide both sides by

- 16

t^{2} = \frac{175}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{175}{16}, t = - \frac{175}{16}

\frac{175}{16} = \frac{5 7}{4}

- \frac{175}{16} = - \frac{5 7}{4}

t = \frac{5 7}{4}, t = - \frac{5 7}{4}

2 + 4 x + 5 = 0

3. 7^{2} = x^{2} + 1. 1^{2}

315 \cdot \frac{π}{180}

\frac{2 i}{( 1 + i )}

- 25 - - 16

What are the solutions to the equation -16t^2+100+75=0 ?
The solutions to the equation -16t^2+100+75=0 are t=(5sqrt(7))/4 ,t=-(5sqrt(7))/4
Find the zeros of -16t^2+100+75=0
The zeros of -16t^2+100+75=0 are t=(5sqrt(7))/4 ,t=-(5sqrt(7))/4