What is (4xy)/(x-2)*(x^2)/(y^2x) ?

The solution to (4xy)/(x-2)*(x^2)/(y^2x) is (4x^2)/((x-2)y)

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simplify (4xy)/(x-2)*(x^2)/(y^2x)

simplify

\frac{4 x y}{x - 2} \cdot \frac{x ^{2}}{y ^{2} x}

\frac{4 x ^{2}}{( x - 2 ) y}

Solution steps

\frac{4 x y}{x - 2} \cdot \frac{x ^{2}}{y ^{2} x}

Cancel

\frac{x ^{2}}{y ^{2} x} : \frac{x}{y ^{2}}

= \frac{4 x y}{x - 2} \cdot \frac{x}{y ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 x y x}{( x - 2 ) y ^{2}}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{4 x ^{2} y}{( x - 2 ) y ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

y^{2} = yy

= \frac{4 x ^{2} y}{( x - 2 ) yy}

Cancel the common factor:

y

= \frac{4 x ^{2}}{( x - 2 ) y}

e^{1^{2}}

5 (3 n - 1) = 80

2 x^{- 3}

(\frac{1}{16})^{- \frac{3}{4}}

\frac{1}{3} \geq \frac{2 x - 9}{12} > \frac{1}{6}

What is (4xy)/(x-2)*(x^2)/(y^2x) ?
The solution to (4xy)/(x-2)*(x^2)/(y^2x) is (4x^2)/((x-2)y)