What are the solutions to the equation x^2-9x-18=0 ?

The solutions to the equation x^2-9x-18=0 are x=(9+3sqrt(17))/2 ,x=(9-3sqrt(17))/2

Find the zeros of x^2-9x-18=0

The zeros of x^2-9x-18=0 are x=(9+3sqrt(17))/2 ,x=(9-3sqrt(17))/2

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x^{2} - 9 x - 18 = 0

x = \frac{9 + 3 17}{2}, x = \frac{9 - 3 17}{2}

Decimal Notation

x = 10.68465 \dots, x = - 1.68465 \dots

Solution steps

x^{2} - 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 18) = 317

x_{1, 2} = \frac{- ( - 9 ) \pm 3 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 17}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3 17}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3 17}{2 \cdot 1} : \frac{9 + 3 17}{2}

x = \frac{- ( - 9 ) - 3 17}{2 \cdot 1} : \frac{9 - 3 17}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 3 17}{2}, x = \frac{9 - 3 17}{2}

0.1 x^{2} - 18.75 x - 250 = 0

3 x - 4 = 5 x - 10

(x - 1)^{4} - 1

∣ 5 x - 14 ∣ = - 6

\frac{4 x ^{2}}{5 y} \cdot \frac{7 y}{12 x ^{4}}

What are the solutions to the equation x^2-9x-18=0 ?
The solutions to the equation x^2-9x-18=0 are x=(9+3sqrt(17))/2 ,x=(9-3sqrt(17))/2
Find the zeros of x^2-9x-18=0
The zeros of x^2-9x-18=0 are x=(9+3sqrt(17))/2 ,x=(9-3sqrt(17))/2