What are the solutions to the equation p^2=-20 ?

The solutions to the equation p^2=-20 are p=2sqrt(5)i,p=-2sqrt(5)i

Find the zeros of p^2=-20

The zeros of p^2=-20 are p=2sqrt(5)i,p=-2sqrt(5)i

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p^{2} = - 20

p = 25 i, p = - 25 i

Solution steps

p^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 20, p = - - 20

- 20 = 25 i

- - 20 = - 25 i

p = 25 i, p = - 25 i

m^{2} - 2 m + 2 = 0

15 x^{2} + 74 x - 32

4 x - 9 > - 1 or - x + 5 \geq 4

∣ 4 x + 3 ∣ = 7

3 a + 9

What are the solutions to the equation p^2=-20 ?
The solutions to the equation p^2=-20 are p=2sqrt(5)i,p=-2sqrt(5)i
Find the zeros of p^2=-20
The zeros of p^2=-20 are p=2sqrt(5)i,p=-2sqrt(5)i