What are the solutions to the equation (x+1)(x+7)=0 ?

The solutions to the equation (x+1)(x+7)=0 are x=-1,x=-7

Find the zeros of (x+1)(x+7)=0

The zeros of (x+1)(x+7)=0 are x=-1,x=-7

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(x + 1) (x + 7) = 0

x = - 1, x = - 7

Solution steps

(x + 1) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

z, - p (d + z) = - 2 z + 59

2 x^{2} + 17 x + 21 = 0

\frac{23}{12} = \frac{1}{2} v + \frac{15}{4} - 6 v

\frac{y}{9} = 3

\frac{6 ^{- 5}}{6 ^{- 2}}

What are the solutions to the equation (x+1)(x+7)=0 ?
The solutions to the equation (x+1)(x+7)=0 are x=-1,x=-7
Find the zeros of (x+1)(x+7)=0
The zeros of (x+1)(x+7)=0 are x=-1,x=-7