What is factor 64+27x^3 ?

The solution to factor 64+27x^3 is (3x+4)(9x^2-12x+16)

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factor 64+27x^3

factor

64 + 27 x^{3}

(3 x + 4) (9 x^{2} - 12 x + 16)

Solution steps

64 + 27 x^{3}

Write in the standard form

= 27 x^{3} + 64

Apply exponent rules

= (3 x)^{3} + 4^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 x)^{3} + 4^{3} = (3 x + 4) (3^{2} x^{2} - 4 \cdot 3 x + 4^{2})

= (3 x + 4) (3^{2} x^{2} - 4 \cdot 3 x + 4^{2})

Simplify

(3 x + 4) (3^{2} x^{2} - 4 \cdot 3 x + 4^{2}) : (3 x + 4) (9 x^{2} - 12 x + 16)

= (3 x + 4) (9 x^{2} - 12 x + 16)

\frac{2}{4} - \frac{2}{6}

5 x = x - 2

k - 7 = - 24

7 x^{2} + 28 = 0

\frac{k ^{14} + 4 k ^{7} + 3}{2 k ^{11} + 2 k ^{4}}

What is factor 64+27x^3 ?
The solution to factor 64+27x^3 is (3x+4)(9x^2-12x+16)