What is the answer to (x-4)^2=(x+2)(x-6) ?

The answer to (x-4)^2=(x+2)(x-6) is x=7

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(x-4)^2=(x+2)(x-6)

(x - 4)^{2} = (x + 2) (x - 6)

x = 7

Solution steps

(x - 4)^{2} = (x + 2) (x - 6)

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

Expand

(x + 2) (x - 6) : x^{2} - 4 x - 12

x^{2} - 8 x + 16 = x^{2} - 4 x - 12

Move

16

to the right side

x^{2} - 8 x = x^{2} - 4 x - 28

Subtract

x^{2} - 4 x

from both sides

x^{2} - 8 x - (x^{2} - 4 x) = x^{2} - 4 x - 28 - (x^{2} - 4 x)

Simplify

- 4 x = - 28

Divide both sides by

- 4

x = 7

1 + 0.4 x - 0.45 x^{2} = 0

2 (x + 2) - 3 (5 - x) = x + 5 (x - 3)

12 \cdot \frac{1}{2}

(2 x - 4)^{2} = 23

(x^{\frac{5}{9}})^{\frac{2}{3}}

What is the answer to (x-4)^2=(x+2)(x-6) ?
The answer to (x-4)^2=(x+2)(x-6) is x=7
Solve for x: (x-4)^2=(x+2)(x-6)
The solution is x=7