What is |x+1|>|x-3| ?

The solution to |x+1|>|x-3| is x>1

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|x+1|>|x-3|

∣ x + 1 ∣ > ∣ x - 3 ∣

x > 1

Interval Notation

(1, \infty)

Solution steps

∣ x + 1 ∣ > ∣ x - 3 ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < 3, x \geq 3

Solve the inequality for each interval

No Solution or 1 < x < 3 or x \geq 3

Merge Overlapping Intervals

x > 1

4 x^{2} + 6 = 34

4 3^{2}

\frac{15 ab}{4} \cdot \frac{8}{9 a ^{2} b ^{2}}

\frac{- 2 - ( - 8 )}{- 1 - 2}