What is 19x+6>7x+10\lor-10+8x>= 12x-6 ?

The solution to 19x+6>7x+10\lor-10+8x>= 12x-6 is x 1/3

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19x+6>7x+10\lor-10+8x>= 12x-6

19 x + 6 > 7 x + 10 or - 10 + 8 x \geq 12 x - 6

x \leq - 1 or x > \frac{1}{3}

Interval Notation

(- \infty, - 1] \cup (\frac{1}{3}, \infty)

Decimal Notation

x \leq - 1 or x > 0.33333 \dots

Solution steps

19 x + 6 > 7 x + 10 or - 10 + 8 x \geq 12 x - 6

19 x + 6 > 7 x + 10 : x > \frac{1}{3}

- 10 + 8 x \geq 12 x - 6 : x \leq - 1

Combine the intervals

x > \frac{1}{3} or x \leq - 1

Merge Overlapping Intervals

x \leq - 1 or x > \frac{1}{3}

4 a < 12

x^{2} - x - 56 < 0

\frac{- 2 x + 6}{x ^{2} - 9}

(\frac{q ^{- 1} r s ^{- 2}}{r ^{- 5} s q ^{- 8}})^{- 1}

8 \leq 2 y + 12 \leq 16

What is 19x+6>7x+10\lor-10+8x>= 12x-6 ?
The solution to 19x+6>7x+10\lor-10+8x>= 12x-6 is x<=-1\lor x> 1/3