What are the solutions to the equation p^2-4p-21=0 ?

The solutions to the equation p^2-4p-21=0 are p=7,p=-3

Find the zeros of p^2-4p-21=0

The zeros of p^2-4p-21=0 are p=7,p=-3

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p^{2} - 4 p - 21 = 0

p = 7, p = - 3

Solution steps

p^{2} - 4 p - 21 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

p_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, p_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

p = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

p = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

p = 7, p = - 3

A = \frac{\frac{3 π}{4} 400}{2}

\frac{\frac{x}{y} - \frac{y}{x}}{\frac{1}{4 x ^{2}} - \frac{1}{4 y ^{2}}}

x^{2} + 8 x + 18 = 0

- \frac{2}{3} + 4

5 x + 4 = 49

What are the solutions to the equation p^2-4p-21=0 ?
The solutions to the equation p^2-4p-21=0 are p=7,p=-3
Find the zeros of p^2-4p-21=0
The zeros of p^2-4p-21=0 are p=7,p=-3