What is 3/4 (8-4c)-9>= 3/8 (16c-24)+10 ?

The solution to 3/4 (8-4c)-9>= 3/8 (16c-24)+10 is c<=-4/9

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3/4 (8-4c)-9>= 3/8 (16c-24)+10

\frac{3}{4} (8 - 4 c) - 9 \geq \frac{3}{8} (16 c - 24) + 10

c \leq - \frac{4}{9}

Interval Notation

(- \infty, - \frac{4}{9}]

Decimal Notation

c \leq - 0.44444 \dots

Solution steps

\frac{3}{4} (8 - 4 c) - 9 \geq \frac{3}{8} (16 c - 24) + 10

Multiply

\frac{3}{4} (8 - 4 c) : \frac{3 ( - 4 c + 8 )}{4}

\frac{3 ( - 4 c + 8 )}{4} - 9 \geq \frac{3}{8} (16 c - 24) + 10

Multiply

\frac{3}{8} (16 c - 24) : \frac{3 ( 16 c - 24 )}{8}

\frac{3 ( 8 - 4 c )}{4} - 9 \geq \frac{3 ( 16 c - 24 )}{8} + 10

Multiply by LCM

24 (- c + 2) - 72 \geq 3 (16 c - 24) + 80

Expand

24 (- c + 2) - 72 : - 24 c - 24

Expand

3 (16 c - 24) + 80 : 48 c + 8

- 24 c - 24 \geq 48 c + 8

Move

24

to the right side

- 24 c \geq 48 c + 32

Move

48 c

to the left side

- 72 c \geq 32

Multiply both sides by

- 1

72 c \leq - 32

Divide both sides by

72

c \leq - \frac{4}{9}

3 x^{2} + 2 = 50

- 8 (5 b)

7 a - 10 = 5 a + 12

\frac{9 a ^{3} b ^{5}}{- 3 a b ^{2}}

- 9 x + 2 > 18 or 13 x + 15 \leq - 4

What is 3/4 (8-4c)-9>= 3/8 (16c-24)+10 ?
The solution to 3/4 (8-4c)-9>= 3/8 (16c-24)+10 is c<=-4/9