What is (9a^3b^5)/(-3ab^2) ?

The solution to (9a^3b^5)/(-3ab^2) is -3a^2b^3

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simplify (9a^3b^5)/(-3ab^2)

simplify

\frac{9 a ^{3} b ^{5}}{- 3 a b ^{2}}

- 3 a^{2} b^{3}

Solution steps

\frac{9 a ^{3} b ^{5}}{- 3 a b ^{2}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{9 a ^{3} b ^{5}}{3 a b ^{2}}

Divide the numbers:

\frac{9}{3} = 3

= \frac{3 a ^{3} b ^{5}}{a b ^{2}}

Cancel the common factor:

a

= \frac{3 a ^{2} b ^{5}}{b ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{b ^{5}}{b ^{2}} = b^{5 - 2}

= 3 a^{2} b^{5 - 2}

Subtract the numbers:

5 - 2 = 3

= - 3 a^{2} b^{3}

- 9 x + 2 > 18 or 13 x + 15 \leq - 4

\frac{x ( x + 6 )}{( x - 7 ) ( x + 1 )} \geq 0

\frac{y ^{8}}{y ^{5}}

xx + 6 = 47

t^{2} - 13 t + 30 = 0