Solution
Solution
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Solution steps
Remove parentheses:
Group like terms
Add similar elements:
Subtract the numbers:
Move to the right side
Divide both sides by
For the solutions are
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Frequently Asked Questions (FAQ)
What are the solutions to the equation (3x^2-4)+(6x^2-8)=0 ?
The solutions to the equation (3x^2-4)+(6x^2-8)=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))Find the zeros of (3x^2-4)+(6x^2-8)=0
The zeros of (3x^2-4)+(6x^2-8)=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))