What are the solutions to the equation k^2-3k=0 ?

The solutions to the equation k^2-3k=0 are k=3,k=0

Find the zeros of k^2-3k=0

The zeros of k^2-3k=0 are k=3,k=0

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k^{2} - 3 k = 0

k = 3, k = 0

Solution steps

k^{2} - 3 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

k_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, k_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

k = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

k = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 3, k = 0

x + (x + 2) = 20 + (x + 4)

(x - 1) (x - 7) \leq 0

5 z^{2} + 4 z - 1 = 0

15 x y + 30 x^{2} y^{2}

(3)^{3}

What are the solutions to the equation k^2-3k=0 ?
The solutions to the equation k^2-3k=0 are k=3,k=0
Find the zeros of k^2-3k=0
The zeros of k^2-3k=0 are k=3,k=0